209_Dynamics 11ed Manual

209_Dynamics 11ed Manual - Engineering Mechanics - Dynamics...

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Engineering Mechanics - Dynamics Chapter 13 F r M r'' r θ ' 2 () = F r 240 N = F Mr '' 2 r' ' + = F 66.0 N = F z M z'' M g + = F z 3.285 N = *Problem 13-84 The path of motion of a particle of weight W in the horizontal plane is described in terms of polar coordinates as r = at + b and = ct 2 + dt . Determine the magnitude of the unbalanced force acting on the particle when t = t 1 . Given: W 5lb = a 2 ft s = b 1f t = c 0.5 rad s 2 = d 1 rad s = t 1 2s = g 32.2 ft s 2 = Solution: tt 1 = ra t b + = r' a = r'' 0 ft s 2 = ct 2 dt + = ' 2 d + = '' 2 c = a r r'' r ' 2 = a r 5 ft s 2 = a r '' 2 r' ' + = a 9 ft s 2 = F W g a r 2 a 2 + = F 1.599 lb = Problem 13-85 The spring-held follower AB has weight
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This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

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