Unformatted text preview: Engineering Mechanics - Dynamics Chapter 13 Given:
M = 50 kg θ' = 1.5 rad
s r0 = 4 m
b = 0.5 m
z = b sin ( θ )
z' = b cos ( θ ) θ'
z'' = −b sin ( θ ) θ' 2 F z − M g = M z'' ( F z = M g − b sin ( θ ) θ'
F zmin = M( g − bθ' ) 2 ) F zmax = M g + bθ' F zmax = 547 N
F zmin = 434 N Problem 13-90
The particle of weight W is guided along the circular path
using the slotted arm guide. If the arm has angular velocity
θ' and angular acceleration θ'' at the instant θ = θ1,
determine the force of the guide on the particle. Motion
occurs in the horizontal plane . θ 1 = 30 deg Given:
W = 0.5 lb a = 0.5 ft rad b = 0.5 ft θ' = 4
θ'' = 8 s
Solution: g = 32.2 ft
2 s θ = θ1 ( a)sin ( θ ) = b sin ( φ ) φ = asin ⎛ sin ( θ )⎞
a ⎝b 211 ⎠ φ = 30 deg ...
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This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.
- Spring '08