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Unformatted text preview: Engineering Mechanics - Dynamics Chapter 13 Given:
W = 2 lb θ 1 = 90 deg
θ' = 4 rad
s b = 2 ft
Solution: θ = θ1 r = bθ r' = bθ' ⎛ rθ' ⎞
⎝ r' ⎠ ψ = atan ⎜ NB = 1 lb Guesses P = 1 lb Given
−NB sin ( ψ) + P cos ( ψ) − W =
P sin ( ψ) + NB cos ( ψ) = ⎛ NB ⎞
⎜ ⎟ = Find ( NB , P)
⎝P⎠ ⎛ W ⎞ ( −r θ' 2 )
⎝g⎠ ⎛ W ⎞ ( 2r' θ' )
ψ = 57.52 deg NB = 3.084 lb *Problem 13-96
The forked rod is used to move the smooth particle of weight W
around the horizontal path in the shape of a limacon r = a + b cosθ. If
θ = ct2, determine the force which the rod exerts on the particle at the
instant t = t1. The fork and path contact the particle on only one side.
W = 2 lb
a = 2 ft
b = 1 ft c = 0.5 rad
2 s 216 P = 2.751 lb ...
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This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.
- Spring '08