226_Dynamics 11ed Manual

226_Dynamics 11ed Manual - Engineering Mechanics - Dynamics...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Engineering Mechanics - Dynamics Chapter 13 Given: a 600 ft = W 130 lb = g 32.2 ft s 2 = v p 80 ft s = Solution: θ 90 deg = ra ( )cos 2 () = Guesses r' 1 ft s = r'' 1 ft s 2 = ' 1 rad s = '' 1 rad s 2 = Given Note that v p is constant so d v p /d t = 0 r' a sin 2 2 ' = r'' a sin 2 2 '' a ( )cos 2 4 ' 2 = v p r' 2 r ' 2 + = 0 r' r'' r 'r '' r' ' + + r' 2 r ' 2 + = r' r'' ' '' Find r' r'' , ' , '' , = r' 0.000 ft s = r'' 42.7 ft s 2 = ' 0.133 rad s = '' 1.919 10 14 × rad s 2 = F N W M r'' r ' 2 = F N W W g r'' r ' 2 = F N 85.3 lb = Problem 13-106 Using air pressure, the ball of mass
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

Ask a homework question - tutors are online