241_Dynamics 11ed Manual

241_Dynamics 11ed Manual - Engineering Mechanics Dynamics...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Engineering Mechanics - Dynamics Units Used: Chapter 13 3 Mm = 10 km Given: e = 0.156 θ = 135 deg hp = 5 Mm G = 66.73 × 10 − 12 m 3 2 kg⋅ s Me = 5.976 × 10 24 kg Solution: 2 G Me ⎞ ⎛ hp v0 Ch 1⎛ ⎜1 − ⎟⎜ e= = 2 ⎟ ⎜ G Me G Me hp ⎜ ⎝ hp v0 ⎠ ⎝ 2 v0 = 1 hp hp G Me( e + 1) 2⎞ 2 ⎟ ⎟ ⎠ hp v v0 = 9.6 km s G Me G Me G Me ⎞ 1 1⎛ ⎜1 − ⎟ cos ( θ ) + = 2⎟ 22 r hp ⎜ hp v0 ⎝ hp v0 ⎠ 1 1⎛ 1⎛ 1 ⎞ 1⎞ = ⎜1 − ⎟ cos ( θ ) + ⎜ ⎟ r hp ⎝ hp ⎝ e + 1 ⎠ e + 1⎠ ⎛ e+1 ⎞ ⎟ ⎝ e⋅ cos ( θ ) + 1 ⎠ r = hp ⎜ r = 6.5 Mm 239 = e+1 ...
View Full Document

This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

Ask a homework question - tutors are online