246_Dynamics 11ed Manual

# 246_Dynamics 11ed Manual - using pieces of flexible tubing...

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Engineering Mechanics - Dynamics Chapter 14 * Problem 14-4 The air spring A is used to protect the support structure B and prevent damage to the conveyor-belt tensioning weight C in the event of a belt failure D . The force developed by the spring as a function of its deflection is shown by the graph. If the weight is W and it is suspended a height d above the top of the spring, determine the maximum deformation of the spring in the event the conveyor belt fails. Neglect the mass of the pulley and belt. Given: W 50 lb = k 8000 lb ft 2 = d 1.5 ft = Solution: T 1 U + T 2 = 0 Wd δ + () + 0 x kx 2 d 0 = Guess 1in = Given Wd + () k 3 3 0 = Find () = 3.896 in = Problem 14-5 A car is equipped with a bumper B designed to absorb collisions. The bumper is mounted to the car
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Unformatted text preview: using pieces of flexible tubing T . Upon collision with a rigid barrier at A , a constant horizontal force F is developed which causes a car deceleration kg (the highest safe deceleration for a passenger without a seatbelt). If the car and passenger have a total mass M and the car is initially coasting with a speed v , determine the magnitude of F needed to stop the car and the deformation x of the bumper tubing. Units Used: Mm 10 3 kg = kN 10 3 N = Given: M 1.5 10 3 kg = v 1.5 m s = k 3 = Solution: The average force needed to decelerate the car is F avg M kg = F avg 44.1 kN = 244...
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## This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

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