250_Dynamics 11ed Manual

# 250_Dynamics 11ed Manual - Engineering Mechanics - Dynamics...

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Unformatted text preview: Engineering Mechanics - Dynamics Chapter 14 x = 10 mm Guess δ ⌠ 1 2 −k x dx − M g r( 1 − cos ( θ ) ) = M v ⎮ 2 ⌡x+ δ Given x = Find ( x) x = 178.9 mm Problem 14-11 The force F , acting in a constant direction on the block of mass M, has a magnitude which varies with the position x of the block. Determine how far the block slides before its velocity becomes v1. When x = 0, the block is moving to the right at speed v0 . The coefficient of kinetic friction between the block and surface is μk.. Given: M = 20 kg c=3 v1 = 5 m s d=4 v0 = 2 m s k = 50 N m μ k = 0.3 g = 9.81 2 m 2 s Solution: NB − M g − Guess c ⎛ ⎞2 ⎜ 2 2 ⎟k x = 0 ⎝ c +d ⎠ NB = M g + c ⎛ ⎞2 ⎜ 2 2 ⎟k x ⎝ c +d ⎠ δ =2m Given 1 2 M v0 + 2 δ δ c ⎛ d ⎞ ⌠ k x2 dx − μ M gδ − μ ⌠ ⎛ ⎞ k x2 dx = 1 M v 2 k k⎮ ⎜ 1 ⎜ 2 2 ⎟⎮ 2 ⌡ 2 2⎟ ⎮ c +d ⎠ c +d ⎠ 0 ⎝ ⌡⎝ 0 δ = Find ( δ ) δ = 3.413 m *Problem 14-12 The force F , acting in a constant direction on the block of mass M, has a magnitude which varies with position x of the block. Determine the speed of the block after it slides a distance d1 . When x = 0, the block is moving to the right at v0 .The coefficient of kinetic friction between the block and surface is μk. 248 ...
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## This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

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