252_Dynamics 11ed Manual

# 252_Dynamics 11ed Manual - of weight W B moves a distance d...

This preview shows page 1. Sign up to view the full content.

Engineering Mechanics - Dynamics Chapter 14 Solution: Observer A: 1 2 Mv 0 2 Fd + 1 2 Mv 2 2 = v 2 v 0 2 2 Fd M + = v 2 6.083 m s = FM a = a F M = a 0.6 m s 2 = Guess t 1s = Given d 0 v 0 t + 1 2 at 2 + = t Find t () = t 1.805 s = Observer B: The distance that the block moves as seen by observer B . d' v 0 v B () t 1 2 at 2 + = d' 6.391 m = 1 2 Mv 0 v B () 2 Fd' + 1 2 Mv' 2 2 = v' 2 v 0 v B () 2 2 Fd' M + = v' 2 4.083 m s = Notice that v 2 v' 2 v B + = Problem 14-14 Determine the velocity of the block A of weight W A if the two blocks are released from rest and the block B
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: of weight W B moves a distance d up the incline. The coefficient of kinetic friction between both blocks and the inclined planes is μ k . Given: W A 60 lb = W B 40 lb = θ 1 60 deg = 2 30 deg = d 2 ft = k 0.10 = Solution: L 2 s A s B + = 2 v A v B + = Guesses v A 1 ft s = v B 1 − ft s = 250...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online