271_Dynamics 11ed Manual

271_Dynamics 11ed - Engineering Mechanics Dynamics Chapter 14 Given M = 2 Mg = 7 deg v = 100 km hr = 0.65 Solution P = M g sin v P eng = P P =

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Engineering Mechanics - Dynamics Chapter 14 Given: M 2Mg = v 100 km hr = θ 7 deg = ε 0.65 = Solution: PM g sin () v = P 66.419 kW = P eng P = P eng 102.2 kW = Problem 14-46 The escalator steps move with a constant speed v . If the steps are of height h and length l , determine the power of a motor needed to lift an average mass M per step.There are n steps. Given: M 150 kg = h 125 mm = n 32 = l 250 mm = v 0.6 m s = dn h = Solution: atan h l = Pn M g v sin = P 12.63 kW
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This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

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