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Unformatted text preview: B 2 M g s 1 + ( ) 2 k A = k B 287 N m = Problem 14-70 Determine the smallest amount the spring at B must be compressed against the block of weight W so that when it is released from B it slides along the smooth surface and reaches point A . Given: W 0.5 lb = b 1 ft = k 5 lb in = Solution: y x ( ) x 2 2 b = T B = V B 1 2 k 2 = T A = V A W y b ( ) = 1 2 k 2 + W y b ( ) + = 2 W y b ( ) k = 1.095 in = 283...
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This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.
- Spring '08