285_Dynamics 11ed Manual

285_Dynamics 11ed Manual - B 2 M g s 1 + ( ) 2 k A = k B...

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Engineering Mechanics - Dynamics Chapter 14 Problem 14-69 Two equal-length springs are “nested” together in order to form a shock absorber. If it is designed to arrest the motion of mass M that is dropped from a height s 1 above the top of the springs from an at-rest position, and the maximum compression of the springs is to be δ , determine the required stiffness of the inner spring, k B , if the outer spring has a stiffness k A . Given: M 2kg = 0.2 m = k A 400 N m = g 9.81 m s 2 = s 1 0.5 m = Solution: T 1 V 1 + T 2 V 2 + = 0 Mg s 1 + () + 0 1 2 k A k B + () 2 + = k
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Unformatted text preview: B 2 M g s 1 + ( ) 2 k A = k B 287 N m = Problem 14-70 Determine the smallest amount the spring at B must be compressed against the block of weight W so that when it is released from B it slides along the smooth surface and reaches point A . Given: W 0.5 lb = b 1 ft = k 5 lb in = Solution: y x ( ) x 2 2 b = T B = V B 1 2 k 2 = T A = V A W y b ( ) = 1 2 k 2 + W y b ( ) + = 2 W y b ( ) k = 1.095 in = 283...
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This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

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