315_Dynamics 11ed Manual

315_Dynamics 11ed Manual - Engineering Mechanics - Dynamics...

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Engineering Mechanics - Dynamics Chapter 15 Solution: 0 Wt 2 b a 2 b 2 + F AB t + W g v = F AB W g vW t + a 2 b 2 + 2 bt = F AB 3.64 kip = Problem 15-19 The block of mass M is moving downward at speed v 1 when it is a distance h from the sandy surface. Determine the impulse of the sand on the block necessary to stop its motion. Neglect the distance the block dents into the sand and assume the block does not rebound. Neglect the weight of the block during the impact with the sand. Given: M 5kg = v 1 2 m s = h 8m = g 9.81 m s 2 = Solution: Just before impact v 2 v 1 2 2 gh + = v 2 12.69 m s = Collision
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