Engineering Mechanics - DynamicsChapter 15Solution:0Wt−2ba2b2+⎛⎜⎝⎞⎟⎠FABt+Wg⎛⎝⎞⎠v=FABWgvWt+⎛⎝⎞⎠a2b2+2bt⎛⎜⎝⎞⎟⎠=FAB3.64 kip=Problem 15-19The block of mass Mis moving downward at speed v1when it is a distance hfrom the sandysurface. Determine the impulse of the sand on the block necessary to stop its motion. Neglectthe distance the block dents into the sand and assume the block does not rebound. Neglect theweight of the block during the impact with the sand.Given:M5kg=v12ms=h8m=g9.81ms2=Solution:Just before impactv2v122gh+=v212.69ms=Collision
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