Engineering Mechanics - DynamicsChapter 15Given:M7Mg=t12s=v40kmhr=t25s=F15kN=t=F215 kN=Solution:The impulse exerted on the plane is equalto the area under the graph.Mv12F1t1+12F1F2+()t2t1−+1=v1v12MF1t1F1F2+t2t1−+⎣⎦+=v116.11ms=Problem 15-30The motor pulls on the cable at A with a force F= a+ bt2. If the crate of weight Wis originally at restat t= 0, determine its speed at time t= t2. Neglect the mass of the cable and pulleys. Hint: First find
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