327_Dynamics 11ed Manual

327_Dynamics 11ed Manual - ⎝ ⎞ ⎠ v c + = v c W 1 W 1...

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Engineering Mechanics - Dynamics Chapter 15 Given: W 1 40 lb = W 2 20 lb = h 15 ft = g 32.2 ft s 2 = Solution: v 1 2 gh = W 1 g v 1 W 1 W 2 + g v 2 = v 2 W 1 W 1 W 2 + v 1 = v 2 20.7 ft s = W 1 g v 1 Imp 0 = Imp W 1 g v 1 = Imp 38.6 lb s = Problem 15-38 A boy of weight W 1 walks forward over the surface of the cart of weight W 2 with a constant speed v relative to the cart. Determine the cart’s speed and its displacement at the moment he is about to step off. Neglect the mass of the wheels and assume the cart and boy are originally at rest. Given: W 1 100 lb = W 2 60 lb = v 3 ft s = d 6f t = Solution: 0 W 1 g v c v + () W 2 g
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Unformatted text preview: ⎝ ⎞ ⎠ v c + = v c W 1 W 1 W 2 + − v = v c 1.88 − ft s = Assuming that the boy walks the distance d t d v = s c v c t = s c 3.75 − ft = Problem 15-39 The barge B has weight W B and supports an automobile weighing W a . If the barge is not tied to the pier P and someone drives the automobile to the other side of the barge for unloading, determine how far the barge moves away from the pier. Neglect the resistance of the water. 325...
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This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

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