328_Dynamics 11ed Manual

# 328_Dynamics 11ed Manual - friction between the block and...

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Engineering Mechanics - Dynamics Chapter 15 Given: W B 30000 lb = W a 3000 lb = d 200 ft = g 32.2 ft s 2 = Solution: m B W B g = m a W a g = v is the velocity of the car relative to the barge. The answer is independent of the acceleration so we will do the problem for a constant speed. m B v B m a vv B + () + 0 = v B m a v m B m a + = t d v = s B v B t = s B m a d m a m B + = s B 18.18 ft = * Problem 15-40 A bullet of weight W 1 traveling at speed v 1 strikes the wooden block of weight W 2 and exits the other side at speed v 2 as shown. Determine the speed of the block just after the bullet exits the block, and also determine how far the block slides before it stops. The coefficient of kinetic friction between the block and the surface is
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Unformatted text preview: friction between the block and the surface is μ k . Given: W 1 0.03 lb = a 3 ft = b 4 ft = W 2 10 lb = c 5 ft = v 1 1300 ft s = d 12 ft = v 2 50 ft s = k 0.5 = Solution: W 1 g ⎛ ⎝ ⎞ ⎠ v 1 d c 2 d 2 + ⎛ ⎜ ⎝ ⎞ ⎟ ⎠ W 2 g ⎛ ⎝ ⎞ ⎠ v B W 1 g ⎛ ⎝ ⎞ ⎠ v 2 b a 2 b 2 + ⎛ ⎜ ⎝ ⎞ ⎟ ⎠ + = 326...
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## This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

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