338_Dynamics 11ed Manual

# 338_Dynamics 11ed Manual - Engineering Mechanics - Dynamics...

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Engineering Mechanics - Dynamics Chapter 15 (vr + vcr cos (θ ))2 + (vcr sin(θ ))2 = vc2 0 = Mr vr + Mc( vr + vcr cos ( θ ) ) ⎛ vc ⎞ ⎜⎟ ⎜ vr ⎟ = Find ( vc , vr , vcr) ⎜v ⎟ ⎝ cr ⎠ vcr = 6.36 m s ⎛ vr ⎞ ⎛ −1.101 ⎞ m ⎜ ⎟=⎜ ⎟ ⎝ vc ⎠ ⎝ 5.430 ⎠ s Problem 15-54 Blocks A and B have masses mA and mB respectively. They are placed on a smooth surface and the spring connected between them is stretched a distance d. If they are released from rest, determine the speeds of both blocks the instant the spring becomes unstretched. Given: mA = 40 kg d =2m mB = 60 kg k = 180 Solution: Guesses N m vA = 1 m s vB = −1 momentum Given 0 = mA vA + mB vB energy m s 121 21 2 k d = mA vA + mB vB 2 2 2 ⎛ vA ⎞ ⎜ ⎟ = Find ( vA , vB) ⎝ vB ⎠ ⎛ vA ⎞ ⎛ 3.29 ⎞ m ⎜ ⎟=⎜ ⎟ ⎝ vB ⎠ ⎝ −2.19 ⎠ s Problem 15-55 Block A has a mass MA and is sliding on a rough horizontal surface with a velocity vA1 when it makes a direct collision with block B , which has a mass MB and is originally at rest. If the collision is perfectly elastic, determine the velocity of each block just after collision and the distance between the blocks when they stop sliding. The coefficient of kinetic friction between the blocks and the plane is μk. Given: MA = 3 kg g = 9.81 m 2 s MB = 2 kg vA1 = 2 m s e=1 μ k = 0.3 336 ...
View Full Document

## This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

Ask a homework question - tutors are online