338_Dynamics 11ed Manual

338_Dynamics 11ed Manual - Engineering Mechanics - Dynamics...

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Unformatted text preview: Engineering Mechanics - Dynamics Chapter 15 (vr + vcr cos (θ ))2 + (vcr sin(θ ))2 = vc2 0 = Mr vr + Mc( vr + vcr cos ( θ ) ) ⎛ vc ⎞ ⎜⎟ ⎜ vr ⎟ = Find ( vc , vr , vcr) ⎜v ⎟ ⎝ cr ⎠ vcr = 6.36 m s ⎛ vr ⎞ ⎛ −1.101 ⎞ m ⎜ ⎟=⎜ ⎟ ⎝ vc ⎠ ⎝ 5.430 ⎠ s Problem 15-54 Blocks A and B have masses mA and mB respectively. They are placed on a smooth surface and the spring connected between them is stretched a distance d. If they are released from rest, determine the speeds of both blocks the instant the spring becomes unstretched. Given: mA = 40 kg d =2m mB = 60 kg k = 180 Solution: Guesses N m vA = 1 m s vB = −1 momentum Given 0 = mA vA + mB vB energy m s 121 21 2 k d = mA vA + mB vB 2 2 2 ⎛ vA ⎞ ⎜ ⎟ = Find ( vA , vB) ⎝ vB ⎠ ⎛ vA ⎞ ⎛ 3.29 ⎞ m ⎜ ⎟=⎜ ⎟ ⎝ vB ⎠ ⎝ −2.19 ⎠ s Problem 15-55 Block A has a mass MA and is sliding on a rough horizontal surface with a velocity vA1 when it makes a direct collision with block B , which has a mass MB and is originally at rest. If the collision is perfectly elastic, determine the velocity of each block just after collision and the distance between the blocks when they stop sliding. The coefficient of kinetic friction between the blocks and the plane is μk. Given: MA = 3 kg g = 9.81 m 2 s MB = 2 kg vA1 = 2 m s e=1 μ k = 0.3 336 ...
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This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

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