356_Dynamics 11ed Manual

356_Dynamics 11ed Manual - Engineering Mechanics Dynamics...

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Engineering Mechanics - Dynamics Chapter 15 v Bx1 1 m s = v Bx2 1 m s = v By1 1 m s = v By2 1 m s = h 1m = d = t 1 1s = t 2 = Given v A cos θ () t 1 a = bv A sin t 1 + 1 2 gt 1 2 h = v By2 v By1 = v A sin 1 v By1 = dv Bx2 t 2 = hv By2 t 2 + 1 2 2 2 0 = v A cos v Bx1 = ev Bx1 v Bx2 = v Bx1 v By1 v Bx2 v By2 h t 1 t 2 d Find v Bx1 v By1 , v Bx2 , v By2 , h , t 1 , t 2 , d , = v Bx1 v By1 8.81 m s = v Bx2 v By2 4.62 m s = d 3.96 m = Problem 15-78 The box of weight W b slides on the surface for which the coefficient of friction is μ k . The box has velocity v when it is a distance d from the plate. If it strikes the plate, which has weight
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This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

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