357_Dynamics 11ed Manual

357_Dynamics 11ed Manual - Engineering Mechanics - Dynamics...

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Engineering Mechanics - Dynamics Chapter 15 Given: W b 20 lb = W p 10 lb = μ k 0.3 = k 400 lb ft = v 15 ft s = e 0.8 = d 2f t = g 32.2 ft s 2 = Solution: Guesses v b1 1 ft s = v b2 1 ft s = v p2 1 ft s = δ 1f t = Given 1 2 W b g 2 μ k W b d 1 2 W b g v b1 2 = W b g v b1 W b g v b2 W p g v p2 + = ev b1 v p2 v b2 = 1 2 W p g v p2 2 1 k δ 2 = v b1 v b2 p2 δ Find v b1 v b2 , v , δ , () = v b1 v b2 v p2 13.65 5.46 16.38 ft = δ 0.456 ft = Problem 15-79 The billiard ball of mass
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This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

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