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364_Dynamics 11ed Manual

# 364_Dynamics 11ed Manual - B as shown If each “stone”...

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Engineering Mechanics - Dynamics Chapter 15 Given: v A 7 m s = m A 8kg = c 12 = e 0.5 = v B 3 m s = m B 6kg = d 5 = Solution: θ atan d c = 22.62 deg = Guesses v A2t 1 m s = v A2n 1 m s = v B2t 1 m s = v B2n 1 m s = Given v B cos () v B2t = v A cos () v A2t = m B v B sin () m A v A sin () m B v B2n m A v A2n + = ev B v A + () sin () v A2n v B2n = v A2t v A2n v B2t v B2n Find v A2t v A2n , v B2t , v B2n , () = v A2t v A2n v B2t v B2n 6.46 0.22 2.77 2.14 m s = v A2 v A2t 2 v A2n 2 + = v A2 6.47 m s = v B2 v B2t 2 v B2n 2 + = v B2 3.50 m s = * Problem 15-88 The “stone” A used in the sport of curling slides over the ice track and strikes another “stone”
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Unformatted text preview: B as shown. If each “stone” is smooth and has weight W , and the coefficient of restitution between the “stones” is e , determine their speeds just after collision. Initially A has velocity v A1 and B is at rest. Neglect friction. Given: W 47 lb = v A1 8 ft s = e 0.8 = 30 deg = 362...
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