367_Dynamics 11ed Manual

367_Dynamics 11ed - cos − = H AO 22.3 kg m 2 ⋅ s = H BO f − m B v B cos em B v B sin = H BO 7.18 − kg m 2 ⋅ s = H CO h − m C n l 2 n 2

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Engineering Mechanics - Dynamics Chapter 15 Solution: r OA c b d = r AB c a d = v A v r AB r AB = H O r OA M v A () × = H O 42.0 0.0 21.0 kg m 2 s = * Problem 15-92 Determine the angular momentum H O of each of the particles about point O . Given: θ 30 deg = φ 60 deg = m A 6kg = c 2m = m B 4kg = d 5m = m C 2kg = e 2m = v A 4 m s = f 1.5 m = v B 6 m s = g 6m = v C 2.6 m s = h 2m = a 8m = l 5 = b 12 m = n 12 = Solution: H AO am A v A sin () bm A v A
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Unformatted text preview: cos ( ) − = H AO 22.3 kg m 2 ⋅ s = H BO f − m B v B cos ( ) em B v B sin ( ) + = H BO 7.18 − kg m 2 ⋅ s = H CO h − m C n l 2 n 2 + ⎛ ⎜ ⎝ ⎞ ⎟ ⎠ v C gm C l l 2 n 2 + ⎛ ⎜ ⎝ ⎞ ⎟ ⎠ v C − = H CO 21.60 − kg m 2 ⋅ s = 365...
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This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

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