378_Dynamics 11ed Manual

378_Dynamics 11ed Manual - Engineering Mechanics - Dynamics...

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Engineering Mechanics - Dynamics Chapter 15 r 8f t = Solution: θ atan h 2 π r θ 9.04 deg = F N W θ () 0 = F N W θ () = F N 790.06 lb = v t v θ () = v t 59.25 ft s = H A t M d + H 2 = 0 t t F N θ () r d W g hv t = F N θ () rt W g hv t = tW v t h F N sin () gr = t 11.9 s = * Problem 15-108 A child having mass M holds her legs up as shown as she swings downward from rest at 1 . Her center of mass is located at point G 1 . When she is at the bottom position = 0 ° , she suddenly lets her legs come down, shifting her center of mass to position G 2 . Determine her speed in the upswing due
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