381_Dynamics 11ed Manual

381_Dynamics 11ed Manual - Engineering Mechanics - Dynamics...

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Engineering Mechanics - Dynamics Chapter 15 v 25 ft s = θ 130 deg = γ w 62.4 lb ft 3 = Solution: QA v = Q 0.69 ft 3 s = t m d d m' = ρ Q = m' w Q = m' 1.3468 slug s = v Ax v = v Ay 0 ft s = v Bx v cos () = v By v sin = F x m' g v Bx v Ax = F x 55.3 lb = F y m' g v By v Ay = F y 25.8 lb = Problem 15-113 Water is flowing from the fire hydrant opening of diameter d B with velocity v B . Determine the horizontal and vertical components of force and the moment developed at the base joint A , if the static (gauge) pressure at A is P A . The diameter of the fire hydrant at
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