410_Dynamics 11ed Manual

# 410_Dynamics 11ed Manual - Engineering Mechanics Dynamics...

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Engineering Mechanics - Dynamics Chapter 16 Given: r A 0.25 in = r B 1in = r C 2.5 in = θ 1 5 rad = k 20 rad s 5 3 = Solution: ω A kt 2 3 = A 3 5 kt 5 3 = t 1 5 1 3 k 3 5 = t 1 0.59 s = A kt 1 2 3 = A 14.09 rad s = B r A r B A = B 3.52 rad s = α A 2 3 kt 1 1 3 = A 15.88 rad s 2 = B r A r B A = B 3.97 rad s 2 = v C r C B = v C 8.81 in s = a C r C B () 2 r C B 2 () 2 + = a C 32.6 in s 2 = Problem 16-21 Due to the screw at E , the actuator provides linear motion to the arm at F when the motor turns the gear at A . If the gears have the radii listed, and the screw at
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## This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

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