This preview shows page 1. Sign up to view the full content.
Unformatted text preview: Engineering Mechanics - Dynamics vB ωAB = rBC ωAB = 4.16 rAC = Chapter 16 rad
s rA sin ( φ ) vA = rAC ωAB rAC = 0.577 m vA = 2.40 m
s Problem 16-79
The shaper mechanism is designed to give a slow cutting stroke and a quick return to a blade attached
to the slider at C. Determine the velocity of the slider block C at the instant shown, if link AB is
rotating with angular velocity ωAB. Solve using the method of instantaneous center of zero velocity.
rAB = 300 mm
rBC = 125 mm ωAB = 4 rad
s θ' = 90 deg
θ 1 = 45 deg
θ 2 = 60 deg
rQB = rBC cos ( θ 1 )
cos ( θ 2 ) rQC = rBC sin ( θ 1 ) + rQB sin ( θ 2 )
vB = ωAB rAB ωBC = vB vC = ωBC rQC rQB 446 vC = 1.64 m
View Full Document
This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.
- Spring '08