448_Dynamics 11ed Manual

# 448_Dynamics 11ed Manual - Engineering Mechanics - Dynamics...

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Unformatted text preview: Engineering Mechanics - Dynamics vB ωAB = rBC ωAB = 4.16 rAC = Chapter 16 rad s rA sin ( φ ) vA = rAC ωAB rAC = 0.577 m vA = 2.40 m s Problem 16-79 The shaper mechanism is designed to give a slow cutting stroke and a quick return to a blade attached to the slider at C. Determine the velocity of the slider block C at the instant shown, if link AB is rotating with angular velocity ωAB. Solve using the method of instantaneous center of zero velocity. Given: rAB = 300 mm rBC = 125 mm ωAB = 4 rad s θ' = 90 deg θ 1 = 45 deg θ 2 = 60 deg Solution: rQB = rBC cos ( θ 1 ) cos ( θ 2 ) rQC = rBC sin ( θ 1 ) + rQB sin ( θ 2 ) vB = ωAB rAB ωBC = vB vC = ωBC rQC rQB 446 vC = 1.64 m s ...
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## This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

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