463_Dynamics 11ed Manual

463_Dynamics 11ed Manual - Engineering Mechanics - Dynamics...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Engineering Mechanics - Dynamics Chapter 16 Solution: ω= vA ω = 30.79 a cos ( θ ) rad s (−a sin ( θ ) + a cos (θ ) )2 + (a sin ( θ )) 2 vD = ω vD = 5.72 Problem 16-102 If the slider block A is moving to the right with speed vA, determine the velocities of blocks B and C at the instant shown. Given: vA = 8 ft s rAD = 2 ft θ 1 = 45 deg rBD = 2 ft θ 2 = 30 deg rCD = 2 ft Solution: rAIC = ( rAD + rBD) sin ( θ 1 ) rBIC = ( rAD + rBD) cos ( θ 1 ) rCID = rAIC + rAD − 2rAIC rAD sin ( θ 1 ) 2 ⎛ rAD φ = asin ⎜ ⎝ rCID 2 ⎞ cos ( θ 1 )⎟ ⎠ γ = 90 deg − φ − θ 2 sin ( γ ) ⎛ ⎞ ⎟ sin ( 90 deg + φ ) ⎠ ⎝ r'CIC = rCD⎜ sin ( θ 2 ) ⎞ ⎛ ⎟ ⎝ sin ( 90 deg + φ ) ⎠ r'DIC = rCD⎜ ωAB = vA rAIC vB = ωAB rBIC vB = 8.00 461 ft s m s ...
View Full Document

Ask a homework question - tutors are online