627_Dynamics 11ed Manual

627_Dynamics 11ed Manual - the point at which it loses...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Engineering Mechanics - Dynamics Chapter 18 Given: W 30 lb = L 10 ft = g 32.2 ft s 2 = Solution: (a) The rod will rotate around point A until it loses contact with the horizontal constraint ( A x = 0). We will find this point first Guesses θ 1 30 deg = ω 1 1 rad s = α 1 1 rad s 2 = Given 0 W L 2 + 1 2 1 3 W g L 2 1 2 W L 2 cos 1 () + = W L 2 sin 1 () 1 3 W g L 2 1 = 1 L 2 cos 1 () 1 2 L 2 sin 1 () 0 = 1 1 1 Find 1 1 , 1 , () = 1 48.19 deg = 1 1.794 rad s = 1 3.6 rad s 2 = (b) Now the rod moves without any horizontal constraint. If we look for
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: the point at which it loses contact with the floor ( A y = 0 ) we will find that this condition never occurs. *Problem 18-52 The slender rod AB of weight W is attached to a spring BC which, has unstretched length L . If the rod is released from rest when = 1 ,determine its angular velocity at the instant = 2 . Given: W 25 lb = 625...
View Full Document

This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

Ask a homework question - tutors are online