635_Dynamics 11ed Manual

635_Dynamics 11ed Manual - Engineering Mechanics - Dynamics...

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Engineering Mechanics - Dynamics Chapter 19 H IC r GIC m ω r GIC I G ω + = H IC I G mr GIC 2 + () = H IC I IC = Q.E.D. Problem 19-3 Show that if a slab is rotating about a fixed axis perpendicular to the slab and passing through its mass center G, the angular momentum is the same when computed about any other point P on the slab. Solution: Since v G = 0, the linear momentum L = mv G = 0. Hence the angular momentum about any point P is H P I G = Since is a free vector , so is H P . Q.E.D. *Problem 19-4 Gear A rotates along the inside of the circular
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This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

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