655_Dynamics 11ed Manual

655_Dynamics 11ed Manual - Engineering Mechanics - Dynamics...

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Engineering Mechanics - Dynamics Chapter 19 Units Used: Mg 10 3 kg = Given: M 1 11 Mg = ω 0 0.6 rad s = v x 400 m s = M 2 54 kg = a 1.5 m = v y 250 m s = k x 1.64 m = k y 3.85 m = b 6m = v z 175 m s = Solution: Angular momentum is conserved. Guess T 1 rad s = Given 02 1 12 M 2 b 2 0 T () M 1 k y 2 T = T Find T = T 0.00 rad s = *Problem 19-36 The platform swing consists of a flat plate of weight W p suspended by four rods of negligible weight. When the swing is at rest, the man of weight W m jumps off the platform when his center of gravity G is at distance a from the pin at A . This is done with a horizontal velocity
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This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

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