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Unformatted text preview: Engineering Mechanics - Dynamics ωG = ωH Chapter 20 rH
rG ωG = 27.778
vE = ωG rA rad
vE = 1.667 m
s vE − ωE rE = ωB rA ωB = vE + ωE rE = ωA rA ωA = vE − ωE rE
vE + ωE rE
rA Problem 20-18
Rod AB is attached to the rotating arm using
ball-and-socket joints. If AC is rotating with
constant angular velocity ωAC about the pin at
C, determine the angular velocity of link BD at
the instant shown.
a = 1.5 ft d = 2 ft b = 3 ft ωAC = 8 rad
s c = 6 ft
Guesses ωBD = 1 rad
s ωABy = 1 rad
s ωABx = 1 rad
s ωABz = 1 rad
Note that ωAB is perpendicular to rAB. 683 ωB = 7.778
ωA = 47.8 rad
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This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.
- Spring '08