742_Dynamics 11ed Manual

742_Dynamics 11ed Manual - Engineering Mechanics Dynamics...

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Engineering Mechanics - Dynamics Chapter 21 T 2 T 1 W a 2 + 1 2 kL 2 b 2 c () 2 = T 2 10.30 lb ft = Second Position Note that B becomes the instantaneous center Guesses v A2 1 ft s = v B2 1 ft s = ω x2 1 rad s = y2 1 rad s = z2 1 rad s = Given 0 0 v A2 x2 y2 z2 L 2 b 2 b 0 × + v B2 0 0 = x2 y2 z2 L 2 b 2 b 0 0 ft s = T 2 1 2 W g L 2 3 x2 2 y2 2 + z2 2 + = v A2 v B2 x2 y2 z2 Find v A2 v B2 , x2 , y2 , z2 , = x2 y2 z2 2.23 1.34 0.00 rad s = v B2 0.00 ft s = v A2 18.2 ft s = Problem 21-33
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This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

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