802_Dynamics 11ed Manual

802_Dynamics 11ed Manual - k 1 3 lb ft = g 32.2 ft s 2 = k...

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Engineering Mechanics - Dynamics Chapter 22 Solution: Since the acceleration of the pendulum is a' g a () = a' 28.2 ft s 2 = Using the result of Example 22-1, we have ω n a' L = ω 4.34 rad s = τ 2 π ω = τ = Problem 22-22 The spool of weight W is attached to two springs. If the spool is displaced a small amount and released, determine the natural period of vibration. The radius of gyration of the spool is k G . The spool rolls without slipping. Given: W 50 lb = r i 1f t = k G 1.5 ft = r o 2f t
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Unformatted text preview: k 1 3 lb ft = g 32.2 ft s 2 = k 2 1 lb ft = Solution: k 1 r o r i + ( ) r o r i + ( ) k 2 r o r i ( ) r o r i ( ) W g k G 2 W g r i 2 + '' = W g k G 2 W g r i 2 + '' k 1 r o r i + ( ) 2 k 2 r o r i ( ) 2 + + = n g W k G 2 r i 2 + ( ) k 1 r o r i + ( ) 2 k 2 r o r i ( ) 2 + = n 2.36 rad s = 800...
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This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

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