833_Dynamics 11ed Manual

833_Dynamics 11ed Manual - and will not oscillate. The...

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Engineering Mechanics - Dynamics Chapter 22 Problem 22-63 Determine the differential equation of motion for the damped vibratory system shown.What type of motion occurs? Given: M 25 kg = k 100 N m = c 200 Ns m = Solution: Mg k y y st + () 2 cy' M y'' = M y'' k y + 2 cy' + ky st + Mg 0 = Equilibrium ky st Mg 0 = M y'' 2 cy' + ky + 0 = (1) y'' 2 c M y' + k M y + 0 = By comparing Eq.(1) to Eq. 22-27 p k M = p 2.00 rad s = c c 2 Mp = c c 100.00 N s m = Since c 200.00 Ns m = > c c 100.00 Ns m = , the system is overdamped
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Unformatted text preview: and will not oscillate. The motion is an exponential decay. *Problem 22-64 The block of mass M is subjected to the action of the harmonic force F = F 0 cos t . Write the equation which describes the steady-state motion. Given: M 20 kg = k 400 N m = F 90 N = C 125 N s m = 6 rad s = 831...
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This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

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