Week 4 quiz notes - over a horizontal distance of 15,841ft....

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Determine the slope of the line M=y2-y1/x2-x1 M =rise/run (0,6) (-5,0) 6-0/0-(-5) 6/5 1 1/5 0-6/-5-0 -6/-5 6/5 1 1/5 Use the intercepts to graph the equation 4x-12=3y X=0 -12=3y -4=y (0,-4) 4x-12=3y Y=0 4x=12 X=3 (3,0) 2.4x+17.6 > 44.0-6.4x 8.8x>26.4 x>3 Graph the equation and identify the Y intercept 4y+3x= -12 X=0 4y= -12 Y= -3 (0,-3) 4y+3x= -12 Y=0 3x= -12 X= -4 (-4,0) Solve. Then graph 4x /> 24 x/>6 (graph with a closed circle because 6 is part of the equation. If it would have been x>6 would have graphed with an open circle)
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Solve using the addition principle 2x+8>x+15 2x-x>15-8 x>7 {x|x>7} Solve using the multiplication principle -4x>1/11 X< - 1/44 Find the slope if it exists X+4y=8 X=0 4y=8 Y=2 (0,2) X+4y=8 Y=0 X=8 (8,0) 2-0/0-8 2/-8 1/-4 -1/4 0-2/8-0 -2/8 -1/4 Find the slope if it exists y = mx + b m is the slope Y=-9x+9 M= -9 From a base elevation of 9600ft, a mountain peak in Colorado rises to a summit elevation of 14,819ft
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Unformatted text preview: over a horizontal distance of 15,841ft. Find the grade of the peak. X=15,841 Y=14,819 Rise/run 14,819/15,841 .94 94% Use the intercepts to graph the equation-x+5y=10 X=0 5y=10 Y=2 (0,2)-x+5y=10 Y=0-x=10 X=-10 (-10,0) Graph the equation and identify the Y intercept Y= -( ½)x-2 X=0 Y= -2 (0,-2) Y= -( ½)x-2 Y=0 0=-.5x-2 .5x=-2 X=-4 (-4,0) The number of people in the chess club is less than or equal to 13. X </ 13 Solve. y-2>-17 y>-15 Graph the line containing the given pair of points and find the slope (-2,5)(3,1) 1-5/3-(-2)-4/5 5-1/-2-3 4/-5 Slope (M)= - 4/5 Solve using the addition and multiplication principles 7+4x<19 4x<12 X<3 {x|x<3}...
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This note was uploaded on 08/13/2011 for the course MAT 116 taught by Professor Universityofphoenix during the Spring '09 term at University of Phoenix.

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Week 4 quiz notes - over a horizontal distance of 15,841ft....

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