This preview shows pages 1–3. Sign up to view the full content.
39.LINEGRAPHS
This section comprises of question in which the data collected in a particular discipline
are represented by specific points together by straight lines. The points are plotted on a two
dimensional plane taking one parameter on the horizontal axis and the other on the vertical axis.
The candidate is required to analyse the given information and thereafter answer the given
questions on the basis of the analysis of data.
SOLVED EXAMPLES
Ex. 1. In a school the periodical examination are held every second month. In a session
during Apr. 2001 – Mar. 2002, a student of Class IX appeared for each of the periodical
exams. The aggregate marks obtained by him in each periodical exam are represented in the
linegraph given below. Study the graph and answer the questions based on it.
(S.B.I.P.O 2003)
MARKS OBTAINED BY A STUDENT IN SIX PERIODICAL EXAMS HELD IN
EVERY TWO MONTHS DURING THE YEAR IN THE SESSION 200102
Maximum Total Marks In each Periodical Exam = 500
1.
The total number of marks obtained in Feb. 02 is what percent of the total marks
obtained in Apr. 01?
(a) 110%
(b) 112.5%
(c) 115%
(d) 116.5%
(e) 117.5%
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document2.
What are the average marks obtained by the student in all the periodical exams of
during the session.
(a) 373
(b) 379
(c) 381
(d) 385
(e) 389
3.
what is the percentage of marks obtained by the student in the periodical exams of
Aug. 01 and Oct. 01 taken together?
(a) 73.25% (b) 75.5%
(c) 77%
(d) 78.75%
(e) 79.5%
4.
In which periodical exams there is a fall in percentage of marks as compared to the
previous periodical exams?
(a) None
(b) Jun. 01
(c) Oct. 01
(d) Feb. 01
(e) None of these
5.
In which periodical exams did the student obtain the highest percentage increase in
marks over the previous periodical exams?
(a) Jun. 01
(b) Aug. 01
(c) Oct. 01 (d) Dec. 01
(e) Feb. 02
Sol. Here it is clear from the graph that the student obtained 360, 365, 370, 385, 400 and 405
marks in periodical exams held in Apr. 01, Jun. 01, Aug. 01, Oct. 01, Dec. 01 and
Feb. 02
respectively.
1.
(b) : Required percentage = [(405/360)*100] % = 112.5 %
2.
(c) : Average marks obtained in all the periodical exams.
= (1/6)*[360+370+385+400+404] = 380.83
≈
381.
3.
(d) : Required percentage = [(370+385)/(500+500) * 100] % = [(755/1000)*100]% =75.5%
4.
(a) : As is clear from graph, the total marks obtained in periodical exams, go on increasing.
Since, the maximum marks for all the periodical exams are same , it implies that the
percentage of marks also goes on increasing. Thus, in none of the periodical exams, there is
a fall
in percentage of marks compared to the previous exam.
5.
This is the end of the preview. Sign up
to
access the rest of the document.
 Spring '11
 vinh

Click to edit the document details