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Unformatted text preview: Click to edit Master subtitle style Radiation Exchange Between Surfaces: Chapter 13 Section 13.2 The gage has a black surface that is 10mm in diameter and is maintained at 17oC by the cooling water. The heater, 200 mm in diameter, has a black surface that is maintained at 800 K. The surroundings and the air are at 27oC and the convection heat transfer coefficient is 15 W/m2K. Plan: a) Governing equation. b) Find view factor. c) Find area. d) Solve for q. e) Solve for net radiation to the gage. The gage has a black surface that is 10 mm in diameter and is maintained at 17oC by the cooling water. The heater, 200 mm in diameter, has a black surface that is maintained at 800 K. The surroundings and the air are at 27oC and the convection heat transfer coefficient is 15 W/m2K. Find the net radiation exchange between the heater and the gage. Governing equation: qhg = AhFhg(Jh – Jg) qhg = AgFgh σ(T h4 – Tg4) The gage has a black surface that is 10 mm in diameter and is maintained at 17oC by the cooling water. The heater, 200 mm in diameter, has a black surface that is maintained at 800 K. The surroundings and the air are at 27oC and the convection heat transfer coefficient is 15 W/m2K. Find the net radiation exchange between the heater and the gage. qhg = AgFgh σ(T h4 – Tg4) The gage has a black surface that is 10mm in diameter and is maintained at 17oC by the cooling water. The heater, 200 mm in diameter, has a...
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This note was uploaded on 08/13/2011 for the course CHEM 3210 taught by Professor Degrazia during the Fall '10 term at Colorado.
 Fall '10
 DEGRAZIA

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