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ch301 exam 1 - Exam 1 mccord(51600 This print-out should...

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– Exam 1 – mccord – (51600) 1 This print-out should have 34 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. c = 3 . 00 × 10 8 m/s h = 6 . 626 × 10 34 J · s m e = 9 . 11 × 10 31 kg R = 3 . 29 × 10 15 s 1 R = 2 . 178 × 10 18 J N A = 6 . 022 × 10 23 mol 1 g = 9 . 81 m/s 2 E = c = λ/ν λ = h p = h mv 1 2 mv 2 = - Φ E n = - R n 2 (hydrogen atom) ν = R parenleftbigg 1 n 2 1 - 1 n 2 2 parenrightbigg - ¯ h 2 2 m d 2 ψ d x 2 + V ( x ) ψ = ψ n ( x ) = parenleftbigg 2 L parenrightbigg 1 2 sin parenleftBig nπx L parenrightBig E n = n 2 h 2 8 mL 2 n = 1 , 2 , 3 , · · · 001 10.0points What is the frequency of light with a wave- length of 4.0 × 10 7 m? 1. 120 s 1 2. 3 . 0 × 10 14 s 1 3. 1 . 3 × 10 15 s 1 4. 7 . 5 × 10 14 s 1 5. 3 . 0 × 10 14 s 1 Explanation: 002 10.0points Assume n 1 and n 2 are two adjacent energy levels of an atom. The emission of radiation with the longest wavelength would occur for which two values of n 1 and n 2 ? 1. 5,4 2. 7,6 3. 8,7 4. 3,2 5. 2,1 6. 6,5 7. 4,3 Explanation: The frequency of a photon emitted when an electron moves between levels n 1 and n 2 is given by the Rydberg equation: ν = R parenleftbigg 1 n 2 1 - 1 n 2 2 parenrightbigg , where R = 3 . 29 × 10 15 Hz. The emission of radiation with the longest wavelength corre- sponds to that with the smallest frequency. From inspection of the formula above we see that ν is smallest when n 1 = 8 and n 2 = 7. Conceptual Solution : E = = h R parenleftbigg 1 n 2 1 - 1 n 2 2 parenrightbigg gives the energy of the pho- tons emitted. The emission of radiation with the longest wavelength corresponds to pho- tons with the smallest energy. From the Bohr frequency condition the energy of the emit- ted photon must be equal to the difference in energy between the higher and lower lev- els. An energy level diagram for the H-atom -`¡Ìi`ÊÜ¡Ì¢ÊÌ¢iÊ`i£¤ÊÛiÀᤥʤvÊ 6¡v¢ÝÊ*À£Ê*,3Ê-`¢Ì£À Ê /¤ÊÀi£¤ÛiÊÌ¢¡ÃÊ¥¤Ì¡Vi]ÊۡáÌ\Ê ÜÜÜ°¡Vi¥¡°V¤£ÉÕ¥¦¤V§°¢Ì£
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– Exam 1 – mccord – (51600) 2 shows that as the energy levels get higher, the gaps between them converge; of the transi- tions listed, the two adjacent levels which are the closest together are n 1 = 8 and n 2 = 7. Thus a transition from n 1 = 8 to n 2 = 7 will result in the emission of a photon with the smallest energy, hence the longest wave- length. 003 0.0points If more points are awarded on this assign- ment, would you like them added to your score? 1. NO, leave my score alone, I prefer the lower score 2. YES, I would like the points and the higher score. Explanation: This should be a no-brainer. Most students want higher scores. If you picked yes, you got credit for the question and you got the extra points you asked for (if they were granted by your instructor). If you answered NO, you also got what you wanted... no points awarded.
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