ch301 exam 2 - – Exam 2 – mccord –(51600 1 This...

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Unformatted text preview: – Exam 2 – mccord – (51600) 1 This print-out should have 35 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 3.0 points The electronic arrangment is the same as the molecular shape when 1. there are more shared electrons than non- shared electrons. 2. there are no lone pairs of electrons on the central atom. 3. the molecule is not polar. 4. the number of bonding orbitals equals the number of anti-bonding orbitals. 5. the atoms are joined by sigma bonds. Explanation: The only time that the molecular shape and electronic arrangement are the same is when there are no lone pairs of electrons on the central atom. 002 3.0 points Which of the following best describes the range of atomic radii? 1. 1 to 15 ˚ A 2. 0.05 to 1 ˚ A 3. 1 to 100 ˚ A 4. 5 to 10 ˚ A 5. 10 to 30 ˚ A 6. 0.4 to 3 ˚ A Explanation: Atomic radii vary from 30 pm (He) to 300 pm (Fr). 1 ˚ A= 10 − 10 m = 100 pm, so the range of atomic radii is 0.3 to 3 ˚ A. 003 3.0 points b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b Which of the following is a radical? 1. BrO 2. CH + 3 3. CH − 3 4. BF − 4 Explanation: Odd valence e − count. 004 3.0 points Which of the following is the best represen- tation of the compound potassium sulfide? 1. 3 K 2+ , 2 bracketleftbigg S bracketrightbigg 3 − 2. K + , bracketleftbigg S bracketrightbigg − 3. K 2+ , 2 bracketleftbigg S bracketrightbigg − 4. K 2+ , bracketleftbigg S bracketrightbigg 2 − 5. 2 K + , bracketleftbigg S bracketrightbigg 2 − 6. None is appropriate because potassium sulfide is a covalent compound. Explanation: The best drawing will show the valence elec- trons, the charges, and the appropriate ratio of ions for K 2 S. 005 3.0 points Given the elements Cl, Ge, and K and the values 418, 1255, and 784 kJ/mol of possible first ionization energies, match the atoms with their first ionization energies. 1. Cl: 418 kJ / mol; Ge: 784 kJ / mol; and K: 1255 kJ / mol 2. Cl: 1255 kJ / mol; Ge: 418 kJ / mol; and K: 784 kJ / mol-`¡Ìi`ÊÜ¡Ì¢ÊÌ¢iÊ`i£¤ÊÛiÀᤥʤvÊ 6¡v¢ÝÊ*À£Ê*,3Ê-`¢Ì£À Ê /¤ÊÀi£¤ÛiÊÌ¢¡ÃÊ¥¤Ì¡Vi]ÊۡáÌ\Ê ÜÜÜ°¡Vi¥¡°V¤£ÉÕ¥¦¤V§°¢Ì£ – Exam 2 – mccord – (51600) 2 3. Cl: 418 kJ / mol, Ge: 1255 kJ / mol; and K: 784 kJ / mol 4. Cl: 1255 kJ / mol; Ge: 784 kJ / mol; and K: 418 kJ / mol 5. Cl: 784 kJ / mol; Ge: 1255 kJ / mol; and K: 418 kJ / mol Explanation: Cl is a Group 7 non-metal and will tend to form a- 1 ion, so it will be very reluctant to give up an electron and will have a very high first ionization energy. K is a group 1 metal and will readily lose an electron to form a +1 ion so the first ionization energy will be very low. Ge will form positive ions and be intermediate in its first ionization energy....
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This note was uploaded on 08/17/2011 for the course CH 301 taught by Professor Fakhreddine/lyon during the Spring '07 term at University of Texas.

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ch301 exam 2 - – Exam 2 – mccord –(51600 1 This...

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