Clearing the LCD - → = 4x 6 x2 3x At this point we need...

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+ + = 1x 1x 3 12 We don’t like fractions, so let’s clear the fractions. To do that, we need to multiply by the LCD. The LCD is going to be (x)(x+3)(2). We use each denominator since no denominator was the exact same. We multiply each fraction by that amount. This is called clearing the fractions. * + * * x x 3 2 + * + * * + = * + * * 1x x x 3 2 1x 3 x x 3 2 12 x * + * * x 3 2 1 + x * x + x 3 * * 2 1 + = x 3 * + * x x 3 * 2 12 + * * x 3 2 + * * 1 x 2 = * + * 1 x x 3 1 Since these are all 1 on the top and we are multiplying, we can drop them. + * + * = x 3 2 x 2 + xx 3 * + * + = x 2 3 2 2x * + * x x x 3 + + = + 2x 6 2x x2 3x At this point, we are going to combine the 2x and 2x on the left side.
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Unformatted text preview: → + = + 4x 6 x2 3x At this point, we need to move everything over with the x² by subtracting 4x and 6. → + 4x 6-- = +--4x 6 x2 3x 4x 6 Combine the 3x – 4x to get -1x =-- 0 x2 1x 6 Now factor this: = - ( + ) 0 x 3 x 2 Now solve for each- = + = : = = -x 3 0 or x 2 0 thus x 3 or x 2 At this point, you could check the answers if you wanted by plugging back into the original equation: + + = 1x 1x 3 12 first try it with x = 3 and then with x = -2. Both answers should check. If one answer gives a 0 in the denominator, we have to throw that answer out. In this example, both answers check....
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This note was uploaded on 08/17/2011 for the course MAT117 MAT 117 taught by Professor Ranjitrebello during the Spring '09 term at University of Phoenix.

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Clearing the LCD - → = 4x 6 x2 3x At this point we need...

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