CP 1 #13 19 and 30 - 3x 4 + 2x 3 – 4x 2 + 9x – 14 #30...

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CP 1 MAT 117 - #13, 19 and 30 Help #13: Evaluate -4x 3 + 9x 2 - 8x – 1 if x = -2 -4(-2 ) 3 + 9(-2 ) 2 – 8(-2 ) – 1 Exponents first -4(-8 ) + 9(4 ) – 8(-2) – 1 Now multiply 32 + 36 – (-16) – 1 The –(-16) will become + 16 32 + 36 + 16 – 1 Now add and subtract from left to right 83 #19 Subtract (3x 4 + 2x 3 – 6) – (4x 2 – 9x + 8) First thing I will do is take care of the subtraction by distributing it throughout the parentheses. This will allow us to drop the parentheses as well. So we will have: 3x 4 + 2x 3 – 6 – 4x 2 – (-9x) – 8 Now I will color code my like terms. I don’t have any x 4 , x 3 , x 2 , or x terms other than one of each of these. So I can’t combine those. I am only able to combine the -6 – 8 part. Let’s put them in order from highest exponent to lowest. 3x 4 + 2x 3 – 4x 2 – (-9x) – 6 – 8 Take care of the – (-9x) and the -6 – 8 we have
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Unformatted text preview: 3x 4 + 2x 3 – 4x 2 + 9x – 14 #30 This is a word problem, and from the word problem, we need to identify our important information. Anything not mentioned below is just (what I call) fluff. We have an equation for the height of an object as: h + vt – 4.9t 2 From this equation, we are told that h = initial height which will be 140 meters v = velocity or speed of item which is 60 t = time which is 3 seconds. We are asked to find the height at time 3 seconds. So we plug each of these into the equation to get 140 + 60(3) – 4.9(3) 2 Follow order of operations Exponents 140 + 60(3) – 4.9(9) Multiply 140 + 180 – 44.1 Add and subtract from left to right 275.9 meters is the height at time 3 seconds....
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This note was uploaded on 08/17/2011 for the course MAT117 MAT 117 taught by Professor Ranjitrebello during the Spring '09 term at University of Phoenix.

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