Factoring 2 - ax2 + bx + c Factoring when a 1 When...

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Factoring ax 2 + bx + c when a ≠ 1 When factoring problems such as 1) 6x 2 -17x – 14 2) 5x 2 – 14x + 8 3) 8x 2 + 38x + 9 I like to factor these by grouping. Trial and error works if you see it right off. If not, it can waste time and build frustration. Factor by grouping is no fail assuming you do the math correct. Let’s take a look at the first problem. 1) 6x 2 -17x – 14 Step 1: Multiply “a” and “c” which are 6 and -14 6 * -14 = -84 Step 2: Look for factors of -84 (‘ac’) that add to ‘b’ which is -17. Factors of -84 add to -17 -1 84 83 1 -84 -83 -2 42 40 2 -42 -40 -3 28 25 3 -28 -25 -4 21 17 4 -21 -17 -6 14 8 6 -14 -8 -7 12 5 7 -12 -5 That’s all the factors of -84. How did I get those? I simply grabbed my calculator and started dividing 84 by 2, 3, 4, … until I got repeats which was at 12. What do I mean by that. When I divided by 8, 9, 10, and 11 I had decimals. 12 went evenly, but I already have 12 listed with 7. Step 3: Now you don’t have to list all the factors because we can stop when we get to the ones that will add up to -17. It is important however, to list your factors in order. So we found 4 and -21 to give us the -17. At this point we will take our question and rewrite the -17x into +4x – 21x. So
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Factoring 2 - ax2 + bx + c Factoring when a 1 When...

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