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Unformatted text preview: Now working the (7) 2 – 4(5)(0) is 49 – 0 = 49. So we have =( )± x 7 4910 Since the √49 = 7, we have =( )± x 7 710 Now the –(7) at the front is really +7. So we have = ± +x 7 710 which is 7 710and 7 710 This will simplify to 14/10 = 7/5 and 0/10 = 0 So our solutions are x = 7/5 and 0. Hope this helps....
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This note was uploaded on 08/17/2011 for the course MAT117 MAT 117 taught by Professor Ranjitrebello during the Spring '09 term at University of Phoenix.
 Spring '09
 RANJITREBELLO

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