Quadratic example 2 for student

Quadratic example 2 for student - Now working the-7 2 –...

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X 2 + 5x – 3 = 0 =- ± - x b b2 4ac2a A = 1, b = 5 and c = -3 =- ±(- ) - (- ) ( ) x 5 5 2 41 3 2 1 Now let’s work the inside part (-5) 2 – 4(1)(-3) = 25 – (-12) = 37 So we have =- ± x 5 372 This is as far as we can go with this problem because 37 can’t be broken down. Now with the other problem 5x 2 - 7x = 0 A = 5, b = -7 and c = 0 =-(- )±(- ) - ( ) ( ) x 7 7 2 45 0 2 5
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Unformatted text preview: Now working the (-7) 2 – 4(5)(0) is 49 – 0 = 49. So we have =-(- )± x 7 4910 Since the √49 = 7, we have =-(- )± x 7 710 Now the –(-7) at the front is really +7. So we have = ± +-x 7 710 which is 7 710and 7 710 This will simplify to 14/10 = 7/5 and 0/10 = 0 So our solutions are x = 7/5 and 0. Hope this helps....
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This note was uploaded on 08/17/2011 for the course MAT117 MAT 117 taught by Professor Ranjitrebello during the Spring '09 term at University of Phoenix.

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Quadratic example 2 for student - Now working the-7 2 –...

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