Lec4_Data_Show_1011

# Lec4_Data_Show_1011 - Lecture 4 Number System CC2202 1 Last...

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CC2202 1 Lecture 4 Number System

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CC2202 2 Last Week and This Week We learnt Intel Processor instructions Bus Structure Timing Diagram We will learn Number System
CC2202 3 Number System We know now that a digital computer stores and manipulates discrete elements of information and all information in the computer is represented in binary form operands used for calculations may be expressed in the binary number system or in the decimal system by means of a binary code the letters of the alphabet are also converted into a binary code In this lecture, we study the binary number system and binary arithmetic

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CC2202 4 Number System Human convention Decimal systems (base 10 or radix 10) 10 separate symbols: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 A decimal number is represented as a n a n-1 ... a 3 a 2 a 1 a 0 . a -1 a -2 a -3 ... a -m The value represented by a digit is implied by its position E.g., 724.5 is interpreted to represent 7 hundreds plus 2 tens plus 4 units plus 5 tenths. The value of the number is computed as follows: 724.5 = 7 × 10 2 + 2 × 10 1 + 4 × 10 0 + 5 × 10 -1 In general, a number in base -r system has coefficients multiplied by power of r: a n r n + a n-1 r n-1 + ... + a 1 r 1 + a 0 r 0 + a -1 r -1 + ... + a -m r -m If a x is equal to 0, it does not contribute to the sum
CC2202 5 Number System - Binary Computer convention -- Binary systems (Base 2) Two symbols: 0, 1 Binary representation: 325 D = 101000101 B Binary addition: basic rules: 0 + 0 = 0 0 + 1 = 1 1 + 0 = 1 1 + 1 = 0 with carry Binary subtraction: basic rules: 0 - 0 = 0 1 - 0 = 1 1 - 1 = 0 0 - 1 = 1 with borrow Binary multiplication and division can be carried out in a manner analogous to that used for decimal numbers but will be considered later

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CC2202 6 Number System: Value box conversion (Integer) Bit Pattern 1 0 0 1 1 1 0 1 Position 7 6 5 4 3 2 1 0 Contributes +2 7 +2 4 +2 3 +2 2 +2 0 The decimal equivalent value of the number 10011101 2 is 2 7 + 2 4 + 2 3 + 2 2 + 2 0 = 128 +16 + 8 + 4 + 1 = 157 10
CC2202 7 Number System: Value box conversion (Fractions) Given the binary number: 10011.101 The value of the number is 2 4 + 2 1 + 2 0 + 2 -1 + 2 -3 = 16 + 2 + 1 + 1/2 + 1/8 = 19 5/8 Bit Pattern 1 0 0 1 1 1 0 1 Position 7 6 5 4 3 2 1 0 Contributes +2 4 +2 1 +2 0 +2 -1 +2 -3

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CC2202 8 Decimal to Binary Conversion (integer)
CC2202 9 Decimal to Binary Conversion (Fractional Numbers) From decimal (F) to binary (0 . R 0 R 1 R 2 …) Consider 0 < F < 1 F x 2 = R 0 + F 1 (R 0 is 0 or 1) F 1 x 2 = R 1 + F 2 (R 1 is 0 or 1) F m-1 x 2 = R m-1 + F m+1 (R m-1 is 0 or 1) The process may run forever, where F The process may run forever, where F m+1 m+1 may not become 0.

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