# 2-21 - CHAP 2 Uniaxial Bar and Truss Elements 121 21...

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CHAP 2 Uniaxial Bar and Truss Elements 121 21. Determine the member force and axial stress in each member of the truss shown in the figure using one of finite element analysis programs in Appendix. Assume that Young‟s modulus is 10 4 psi and all cross-sections are circular with diameter of 2". Compare the results with the exact solutions that are obtained from free-body- diagram. Solution: (a) Exact solution: The Free-Body-Diagram of the structure becomes: Member BC is a zero-force member. Thus, the force and stress in BC will be zero. Moment equilibrium: 36 24 1200 9 400 0 900 lb A FY FY MF F  Next, using the joint method, solve for the internal forces in members DF and EF . 4 0 5 3 900 0 5 1500 lb, 1200 lb X EF DF Y DF DF EF F F F FF     Therefore 900 lb F EF F DF F 400 lb 1,200 lb A B C D E F F AX F AY F FY 12' 12' 12' 9' 400 lb 1,200 lb Material: Steel rod Diameter: 2"

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122 Finite Element Analysis and Design 1500 477.5 psi 1200 382 psi DF EF       (b) Finite element solution: We will use the MATLAB toolbox in Appendix D for finite
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## This note was uploaded on 08/22/2011 for the course EML 4500 taught by Professor Staff during the Fall '08 term at University of Florida.

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2-21 - CHAP 2 Uniaxial Bar and Truss Elements 121 21...

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