{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# 4-28 - 256 Finite Element Analysis and Design 28 The frame...

This preview shows pages 1–2. Sign up to view the full content.

256 Finite Element Analysis and Design 28. The frame shown in the figure is subjected to some forces at Nodes 2 and 3. The resulting displacements are given in the table below. Sketch the axial force, shear force, and bending moment diagrams for Element 3. What are the support reactions at Node 4? Assume EI =1000 N-m 2 and EA =10 7 m 2 . Length of all elements = 1 m. Node u (mm) v (mm) (radian) 2 10 1 -0.1 3 11 -1 +0.1 Solution: For Element 3, choose the local coordinates x y as shown. That means the first Node is 4 and the second node is 3. Then the angle = 90 o . The displacements for this element can be transformed local coordinates as follows 4 4 4 4 4 4 3 3 3 3 3 3 0 1 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 1 0 0.011 0 0 0 1 0 0 0.001 0 0 0 0 0 1 0.1 u u v v u u v v  

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 2

4-28 - 256 Finite Element Analysis and Design 28 The frame...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online