9.19 - 3K PRoeabéM ‘M ‘i W An m'r—swndard Dt'esej...

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Unformatted text preview: 3K PRoeabéM ‘M ‘i W: An m'r—swndard Dt'esej cycle has a. specified Sw‘afe 0.4414 bead/mm of COM/WeSSlon and a. known pressure and fem/)eragum af HM and of had addifl'm. FIND: Defermdoe (a) +1sz compresgion mfi'on) +Le WOFF rafio)(c) Me fiermal eGFc'u‘emod , and (d) Ike me’am eFFedWQ Jimsqm. SCHeMMlC $9.:SV66! ”fl: F a: PL5P3:7.7—MPA:7‘LOORP& _ 2’50 E k ‘ our Ila ‘ I 833521)“ fiszgmgflaas: See, Example 4.2.. W'- Begin by fixing each Pn‘vxciga‘ 5+ode. in HM §cle CTableA-Zz). aim: T,=300 K, 3:?3 kPa =€> at = 2mm tar/L3 , 145011.75 331.3860 Qmjggz: For Hm z‘semi'ropic. compressibn Pra.‘ Fr. (-22?) =(L38(903(7:oso) 3 ‘05—'04 Thus; T1: 6116:.“ ,v-m=2<..1qz J EB Wing“: 5mm: 7;:2150 K, 73:1100 we; => («3 aqua-315% ,u;3= 2.113 51mg“ For Hm. Isemh'opic axPamsioM ”2: U1: 12.12. - 15g 1; - 0“" “7““:(030 —. — U; ”2. v3 31 1'3 ’ «yr "1:; " 20.1013 2:50 '1. 4f _. .—. ”m = 32.5,: = 21x13; =§>1~Lt =(ou K, uq 425.73 Ind/kg (a) The compression radio is -2. = 15:: - com Cs 3 Y- 01 «In 35.1% 23.xqa_—___________. (b) The <4).wa Milo is (c) The Mrmal cf—Ctkneucg Lr wade/M Gas-4‘1.) “UM-Uh) W a am» [434% _ (IRMA—(021.83.)- 135.7: ~2N.01) - (tumors —-(ou..%z.$ 9015.90 __ 0 ~ m ‘OS‘CI'I (SOL-M) ' M, (1'3! PROBLEM 0L \ 0: (Covfi'd) (d) The mum eQGeoHve Pressure is 361w as Wadde Waade, (VM me 1 ___- : 1) V1." V7. ’LfiU‘VL/vj) Evauurhkg vj 5.5!! (5T 1}” RT: _ 283ka)(30010 1ch». 1035”“ l P: (615 kPa) 'lOsN/m" 1 Hr = 0.610(93 M345 Thus MP=MJ°WN W’a I \kJ“ ‘ low/m2, (030cc: 353) (1- VWM = C115. ‘L V0» *_______ __ ___—___ ___ .___________..___E_.Vhe’ . 4-32 ...
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