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5_Problem_Examples

# 5_Problem_Examples - Ch.5#5 = 40 Example Problems Ch 5 = 7...

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Example Problems, Ch. 5 Ch.5, #5 μ = 40 σ = 7 X z 45 51 41 30 25 38 Ch.5, #5 μ = 40 σ = 7 X z 45 51 41 30 25 38 z = X μ σ Ch.5, #5 μ = 40 σ = 7 X X μ z 45 51 41 30 25 38 z = X μ σ

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Ch.5, #5 μ = 40 σ = 7 X X μ z 45 5 51 41 30 25 38 z = X μ σ Ch.5, #5 μ = 40 σ = 7 X X μ z 45 5 51 11 41 30 25 38 z = X μ σ Ch.5, #5 μ = 40 σ = 7 X X μ z 45 5 51 11 41 1 30 -10 25 -15 38 -2 z = X μ σ Ch.5, #5 μ = 40 σ = 7 X X μ z 45 5 / 7 = 0.71 51 11 41 1 30 -10 25 -15 38 -2 z = X μ σ
Ch.5, #5 μ = 40 σ = 7 X X μ z 45 5 / 7 = 0.71 51 11 / 7 = 1.57 41 1 / 7 = 0.14 30 -10 / 7 = -1.43 25 -15 / 7 = -2.14 38 -2 / 7 = -0.29 z = X μ σ Ch.5, #7b μ = 40 σ = 8 z X 0.75 1.50 -2.00 -0.25 -0.50 1.25 Ch.5, #7b μ = 40 σ = 8 z X 0.75 1.50 -2.00 -0.25 -0.50 1.25 z = X μ σ

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Ch.5, #7b μ = 40 σ = 8 z X 0.75 1.50 -2.00 -0.25 -0.50 1.25 X = μ + ( z )( σ ) Ch.5, #7b μ = 40 σ = 8 z ( z )( σ ) X 0.75 1.50 -2.00 -0.25 -0.50 1.25 X = μ + ( z )( σ ) Ch.5, #7b μ = 40 σ = 8 z ( z )( σ ) X 0.75 6 1.50 -2.00 -0.25 -0.50 1.25 X = μ + ( z )( σ ) Ch.5, #7b μ = 40 σ = 8 z ( z )( σ ) X 0.75 6 1.50 12 -2.00 -16 -0.25 -2 -0.50 -4 1.25 10 X = μ + ( z )( σ )
Ch.5, #7b μ = 40 σ = 8 z ( z )( σ ) X 0.75 6 + 40 = 46 1.50 12 -2.00 -16 -0.25 -2 -0.50 -4 1.25 10 X = μ + ( z )( σ ) Ch.5, #7b μ = 40 σ = 8 z ( z )( σ ) X 0.75 6 + 40 = 46 1.50 12 + 40 = 52 -2.00 -16 + 40 = 24 -0.25 -2 + 40 = 38 -0.50 -4 + 40 = 36 1.25 10 + 40 = 50 X = μ + ( z )( σ ) Ch.5, #11 X value corresponding to z = 0.25 for distributions with: μ = 40 σ = 4 μ = 40 σ = 8 μ = 40 σ = 12 μ = 40 σ = 20

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Ch.5, #11 X value corresponding to z = 0.25 for distributions with: μ = 40 σ = 4 μ = 40 σ = 8 μ = 40 σ = 12 μ = 40 σ = 20 X = μ + ( z )( σ ) Ch.5, #11 X value corresponding to z = 0.25 for distributions with: μ = 40 σ = 4 40 + (0.25)(4) μ = 40 σ = 8 μ = 40 σ = 12 μ = 40 σ = 20 X = μ + ( z )( σ ) Ch.5, #11 X value corresponding to z = 0.25 for distributions with: μ = 40 σ = 4 40 + (0.25)(4) = 41 μ = 40 σ = 8 μ = 40 σ = 12 μ = 40 σ = 20 X = μ + ( z )( σ ) Ch.5, #11 X value corresponding to z = 0.25 for distributions with: μ = 40 σ = 4 40 + (0.25)(4) = 41 μ = 40 σ = 8 40 + (0.25)(8) μ = 40 σ = 12 μ = 40 σ = 20 X = μ + ( z )( σ )
Ch.5, #11 X value corresponding to z = 0.25 for distributions with: μ = 40 σ = 4 40 + (0.25)(4) = 41 μ = 40 σ = 8 40 + (0.25)(8) = 42 μ = 40 σ = 12 μ = 40 σ = 20 X = μ + ( z )( σ ) Ch.5, #11 X value corresponding to z = 0.25 for distributions with: μ = 40 σ = 4 40 + (0.25)(4) = 41 μ = 40 σ = 8 40 + (0.25)(8) = 42 μ = 40 σ = 12 40 + (0.25)(12) μ = 40 σ = 20 X = μ + ( z )( σ ) Ch.5, #11 X value corresponding to z = 0.25 for distributions

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5_Problem_Examples - Ch.5#5 = 40 Example Problems Ch 5 = 7...

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