10_Problem_Examples

10_Problem_Examples - Ch.10, #9a,b,c Example Problems, Ch....

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Example Problems, Ch. 10 Ch.10, #9a,b,c Sample 1: n 1 = 12 SS 1 = 1740 Sample 2: n 2 = 12 SS 2 = 1560 Ch.10, #9a,b,c Sample 1: n 1 = 12 SS 1 = 1740 Sample 2: n 2 = 12 SS 2 = 1560 a. Pooled variance Ch.10, #9a,b,c Sample 1: n 1 = 12 SS 1 = 1740 Sample 2: n 2 = 12 SS 2 = 1560 a. Pooled variance
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Ch.10, #9a,b,c Sample 1: n 1 = 12 SS 1 = 1740 Sample 2: n 2 = 12 SS 2 = 1560 a. Pooled variance = (1740 + 1560) / (12–1 + 12–1) Ch.10, #9a,b,c Sample 1: n 1 = 12 SS 1 = 1740 Sample 2: n 2 = 12 SS 2 = 1560 a. Pooled variance = (1740 + 1560) / (12–1 + 12–1) = 3300 / 22 Ch.10, #9a,b,c Sample 1: n 1 = 12 SS 1 = 1740 Sample 2: n 2 = 12 SS 2 = 1560 a. Pooled variance = (1740 + 1560) / (12–1 + 12–1) = 3300 / 22 = 150.00 Ch.10, #9a,b,c Sample 1: n 1 = 12 SS 1 = 1740 Sample 2: n 2 = 12 SS 2 = 1560 a. Pooled variance = (1740 + 1560) / (12–1 + 12–1) = 3300 / 22 = 150.00 b. Estimated standard error
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Ch.10, #9a,b,c Sample 1: n 1 = 12 SS 1 = 1740 Sample 2: n 2 = 12 SS 2 = 1560 a. Pooled variance = (1740 + 1560) / (12–1 + 12–1) = 3300 / 22 = 150.00 b. Estimated standard error Ch.10, #9a,b,c Sample 1: n 1 = 12 SS 1 = 1740 Sample 2: n 2 = 12 SS 2 = 1560 a. Pooled variance = (1740 + 1560) / (12–1 + 12–1) = 3300 / 22 = 150.00 b. Estimated standard error = 150 / 12 + 150 / 12 Ch.10, #9a,b,c Sample 1: n 1 = 12 SS 1 = 1740 Sample 2: n 2 = 12 SS 2 = 1560 a. Pooled variance = (1740 + 1560) / (12–1 + 12–1) = 3300 / 22 = 150.00 b. Estimated standard error = 150 / 12 + 150 / 12 = 25 = 5.00 Ch.10, #9a,b,c Sample 1: n 1 = 12 SS 1 = 1740 Sample 2: n 2 = 12 SS 2 = 1560 a. Pooled variance = (1740 + 1560) / (12–1 + 12–1) = 3300 / 22 = 150.00 b. Estimated standard error = 150 / 12 + 150 / 12 = 25 = 5.00 c. Two-tailed test, α = .05 Difference between means = 8.00
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Ch.10, #9a,b,c n 1 = 12 SS 1 = 1740 n 2 = 12 SS 2 = 1560 s 2 p = 150.00 s ( M 1 M 2 ) = 5.00 c. Two-tailed test, α = .05 Difference between means = 8.00 Ch.10, #9a,b,c n 1 = 12 SS 1 = 1740 n 2 = 12 SS 2 = 1560 s 2 p = 150.00 s ( M 1 M 2 ) = 5.00 c. Two-tailed test, α = .05 Difference between means = 8.00 Ch.10, #9a,b,c n 1 = 12 SS 1 = 1740 n 2 = 12 SS 2 = 1560 s 2 p = 150.00 s ( M 1 M 2 ) = 5.00 c. Two-tailed test, α = .05 Difference between means = 8.00 t obs = 8.00 / 5.00 Ch.10, #9a,b,c n 1 = 12 SS 1 = 1740 n 2 = 12 SS 2 = 1560 s 2 p = 150.00 s ( M 1 M 2 ) = 5.00 c. Two-tailed test, α = .05 Difference between means = 8.00 t obs = 8.00 / 5.00 = 1.60
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Ch.10, #9a,b,c n 1 = 12 SS 1 = 1740 n 2 = 12 SS 2 = 1560 s 2 p = 150.00 s ( M 1 M 2 ) = 5.00 c. Two-tailed test, α = .05 Difference between means = 8.00 t obs = 8.00 / 5.00 = 1.60 df = df 1 + df 2 Ch.10, #9a,b,c n 1 = 12 SS 1 = 1740 n 2 = 12 SS 2 = 1560 s 2 p = 150.00 s ( M 1 M 2 ) = 5.00 c. Two-tailed test, α = .05 Difference between means = 8.00 t obs = 8.00 / 5.00 = 1.60 df = df 1 + df 2 = 11 + 11 = 22 Ch.10, #9a,b,c n 1 = 12 SS 1 = 1740 n 2 = 12 SS 2 = 1560 s 2 p = 150.00 s ( M 1 M 2 ) = 5.00 c. Two-tailed test,
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This note was uploaded on 08/22/2011 for the course PSY 207 taught by Professor Pfordesher during the Fall '07 term at SUNY Buffalo.

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10_Problem_Examples - Ch.10, #9a,b,c Example Problems, Ch....

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