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Unformatted text preview: You start out with the equation 2x^2+76x+430 Since 38 is half of 76, and 215 is half of 430 you would say. . 2(x^238x215) Next, 5+38=43 so. .. 2(x^243x+5x215) then, take your double x's and write like so. . 2(x(x43)+5(x43) (since 5(43)=215) Finally, 2 (x+5)(x43) is the answer because. ... (215(2)=430) Use your equation from part (c) to find N for each year in the table . For 1993, putting x=0, N=2(043)(0+5)= 430 4 For 1995, putting x=2, N=2(243)(2+5) = 574 4 For 1997, putting x=4, N=2(443)(4+5) = 702 4 For 1999, putting x=6, N=2(643)(6+5) = 814 4 For 2001, putting x=8, N=2(843)(8+5) = 910 4 For 2003, putting x=10, N=2(1043)(10+5) = 990 Are the Answers the Same Yes they are both the same Questions...
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 Spring '09
 ALKOFAHI
 Math, 1920, 1916, 1918, 1912, 1908, 1917

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