File Tutorial2withAnswers - Tutorial 2 14 Problem 4—33...

Info icon This preview shows pages 1–12. Sign up to view the full content.

View Full Document Right Arrow Icon
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
Image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 4
Image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 6
Image of page 7

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 8
Image of page 9

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 10
Image of page 11

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 12
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ' Tutorial 2 14* Problem 4—33 _ The steel pipe is filled with concrete and subjected to a - compressive force of 80 kN. Determine the stress in the concrete and the steel due to this loading. The pipe has an outer diameter of 80 mm and an inner diameter of 70 mm. Est = 200 GPa, E0 = 24 GPa_ 0 SOkN W + T 21", = , P5: +IPc0n - 30 = 5,, = 5cm: Pu L 35 (0.032 — 0.071) (200) (10") P“ = 2;5510P:on a; = 57mm Pm = 22 a”: E'. = 5147 (10?) A“ §(0.082 - 0.07?) pm.” 22.53 (103). 0,, 4E (0.071} (1) Pm L g (0.072) (24) (109) (2) = 48.8 MPa Ans 5.35 MP3 Ans Problem 4-7 The steel bar has the original dimensions shown in the figure. If it is subjected to an axial load of 50 kN, determine the change in its length and its new cross-sectional dimensions at section a—a. Est : 200 GPa, v 2 0.29. Solution 4-7 5 = 55 a 2(50x10’x200) + 50(103x350) ”’9 AE (0.02)(0.05)(2uo}(109) (0.06)(0.05)(200){109) = 0.129 mg: Ans - 5M: = £1: = SOOOJXSSO) = 0.92917-mm AE (0.06)(0.05)(200)(109) 53¢ 1.; Eli 0:929” = 000003333 Lac 350 ‘ a,“ = -ve,m,g = — (0.29)(0.00003333) = -o.eoooz417 h’ = so - 50 (000002417) = 49.9988 mm Ans w‘ = so — 60(0.00002417) = 59.9935 mm Ans 4-33 The steel pipe is filled with concrete and subjected to x . n compressive force of 80 H4. Determine the stress in the - - 3 annual: and the sleel due io this handing, The pipe has an , outer diameter of 90 mm and an inner diameler of 70 mm. r . E" = 200 Oh, .E‘ = ‘24 GPa. . 80"“ +ng=o; PS,+PM,.—30=0 (1) a.” : 5cm! at ‘ ILL E PmL f Fa... 45(0382 — (1072-) (200) (109) 3’! (0.071) (‘24) (109) P5‘ 2.551019“... (2) ‘ Ii Solving Eqs. (1) and (2) yields Pu 2: 57.47kN Pm,I = 22.53kN 3 a, = E = 57"“ (10) = 48.8 MPa Ans ’ A” gains! — 0.072) 3 I I , am 5223.: 2253“”) = 5.35 MPa Ans Am. 4% (0.07:) 4-34. The concrete column is reinforced using four steel reinforcing rods, each having a diameter of 18 mm. Determine the stress‘in the concrete and the steel if the ' _ column is subjected to an axial load of 800 kN. E“ = 20:) GPa, EC = 25 GPa. Equilibrium .' +TEE=0: mmnmsoow r11 Campaliibilily .- 61: =5 can p” (L) PM (L) w ; W 4(T)(0,0183)(2003(109) [o.3_1_4(§) (110131)] (15) (109) a, =o.09i513 a," (2] Solw'ng Eqs. [I] and [2] yields : P“ = 61072 or Pm = 731.923 1m Average Normal Sn“ .- 6 _ -67.012( ml) _659MP " Mammo— ' a , A“ 732.9zsuo!) C"... = -——-—---—._.._._ = 3.24 MP: [0.32 _4( 41) (93132)] A” “3%; 143 Th: bar has a langth L and crassasectiunal area A. Dttnnnim: its clungatinn due In both the. fame. P and it: awn weight. Th: matarial has a specific weight 1.: {weightfinlumt} and a modulus nf elasticity E. (A) 2 - z ‘ 1 ML yL PL Ans ._- The Issgmbiy consists 0! than titanium rods and a rigid bar 411 Th: cross’aecliunal area of each rod is givan in‘ the figure. If u vanicni force of P = 20 RN is applied to the ring P. determine the vertical displacemenl of pain! F. 8,; a 350 GPu. PL 12(103)(2000) 5‘ =__= =1.1429mm AE (60)(10")(350)(10") 5c = ~11 = 8(103)(2000) = 1.0159 mm AE 45(10'“)(350)(109) a 61.71; = PL 3 m = 1.1429 mm AT: 75(106)(350)(1o°) 5; = 1.0159 +[I)'—Z?(11270) = 1.092 mm 5:: = 5F. + ENE. ‘, = 2.23 mm Ans 13‘: China 9-15.“ I “WHEEE; = 1392+ 1.1429 / I. (42—! 10:5“? 5 a. {2. M mm. 130 ‘ 4-11 The truss is made of Ito-:2 A-36 steel members. each having aqoss-uehtional ma nf400mm1. Determine the hur— - ' § izantsl displacement of the roflnr at C when P t 8 kN. ' ., ' By observation the horizontal displacement of roller C is equal to the displacement of point C obtained from member AC. Fm =5.571kN FEAL 5.571(103)(1.40) Cl=_—= = 0,0975 mm Ans AE (400)(10'5)(200)(106) ’34:: 127 4-5 The A-afi steel rod is subjeeled lo the loading shown ll_l.l_ie cross-se’cliunal area of the rod is 60 mmi. deletmine '. the displacement at H and A. Neglect the size of the cun- " gt at B. C. and D. £2195: 16.116 (103M035) + 10.4(103)(1.50) AE 60(106)(200)[1o°) 60(10‘)(200)(109) "-= 0.00231m = 2.31mm Ans a (103mm = .00264 = . 60(10‘5)(200)(109l 0 m 264mm Ans ‘53-!- ”.1115 mid-T6 aluminum rod has a dinmeler a! Si] mm ltd lupput'ls the load shown. Determine the displacement [A with respect to E. Neglect the size of the couplings. - PL 1 .= 2—- = —{8(4) +4(2)—2(2)+0(2)](103) AE {LE 1..— MN ; 36(103' F ‘ ) - -3 m- %(o.oa)1(73.1)(109) "0'69? “0 ”“697 mm A” “M «w “M 4d The assembly consists of 1 steel rod CB and an alu- minum rod BA.euch having a diameter of12 mm. if the rod ’ I“ "Is subjected to the axial landings II A and at the coupling B, ‘ determine the displacement of the coupling B and the end ' A. The unmatched length of each segment is shown in the ' ' 7:. figure. Neglect the size of the connections at B and. C, and astume that they are rigid. 15,. = 200 69a. Ear= 70 GPa. ie' f C B A E! om [HEN p; m 4...: 16 "‘4 “Hem—v FEE-u}. em a H H 1' K 1%‘3/8 ‘—-~«—c:—~ a, =55 = M =0.00159 m =1.59 mm Ans AE 1.1(0.012)2(200)(109) PL 12mins) 18(10’)(2) 4...__._...-————-—' $81012)2 (200)(10") 450.012)2 (70)(109) 8A:Z—-—= AE 0.00614 [11 s 6.14 mm Ans 4&1 The composite shaft. consisting of aluminum. copper. . and steel sections. is subjected to the loading shown. Determine the displacement of endA with respect In and D and the normal stress in each section. The cross-sectional area and modulus of elastlclty for each section are shown in the figure. Neglect the size of the canine at E and C. &T;%Ehl Lima“ extol)“ P 4”“. m1 alumni]: AcnID-ufihfl .43 a” =.— = Au Per: 0' =——— no Am: c . 2%. - ‘ . /- “= - 2W - 6 a E- 2(13) + (—sxm + ,(.-1.5)(1-6)\. *_t__.—__t—a— fife"? MD AE (0‘09)(10)(103) (0.12)(18)(]03} #. _ JLFP = — (100157111. Ans \\ , 1-55 x fang" P The negative Sign indicates endA move‘sfi'éwards end D. " 121 E31 Th: wnlpusile bar cansisls of a 20-mm-diameter A. j and augment AB and SCI-mmvrliameler rad brass C3340!) r dugmnnu DA and CB. Determine the average normal is: In each segment due to the applied load. _ 9A." My chFD+75+75—100—100=0 Fc—FD—50=0 (1) AD ~' 51) 150(0.5) _ 50(0.25) $(0.02)‘(200)(109) §(0.053)(101)(109) FD{0.5) Fn(0.5) 3"5(0.051)(101)(109) $(U.02)z(200)(lfl9) , a ._ = . A} F]; = 107.89kN "W5: "7”" 3mm), Fg = 157.89kN A PM) 107.a9(103) — = ‘ = 55.0 MP2 Ans Aw 45(0-052) Pu""”""'1mam — P” — 42.11003) = 134mm Ans A“; , £0,022) _ ‘- ch 15189003) = 80.4 MPa Ans . Am $0.052) , -_ The mmposiac bar consists of a Emmi-diameter A— lec! segment AB and SO-mm-diamcter red brass C834Dfl segments DA and CB. Dmerminc the displacnmcnl of Rh respacl 10 8 1111: lo the applied load. 0 = AD— 5.0 0 : 150(105)(500) _ 50(103)(250) ' 25(0.02)2(200)(109) W - fl - moo) ‘ §(0.052)(101)(109) W -._Fa = 107.89kN Placemant : ‘ ‘ Pam 42,11(103)(500) Auk]. 45(0.021)200( 109) Mlm 0.335 mm . A,“ w‘figi_ 145 . , § ...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern