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Unformatted text preview: Tutorial 8 w Problem 54 ' The copper pipe has an outer diameter of 40 mm and an
inner diameter of 37 m. If it is tightly secured to the wall
at A and three torques areapplied to it as shovtm, determine the absolute maximum shear stress developed in the pipe. %*2_ Problem Sll The shaft consists of three concentric tubes, each made
from the same material and having the inner and outer
radii shown. If a torque of T = 800 Nm'is applied to the
rigid disk ﬁxed to its end, determine the maximum shear stress inthe shaft. E—é "Solution 511 J = g ( (0.038)‘  (0.032)‘ J + 3% (0.03504 — (0326)“) + .2’5 ( (0.025)“ — (0.020314) J = 2.545(106)m4 T .
rm = J = MW 038) =11.9 MPa Ans 
J 1545(106)  Problem 512 The solid shaft is ﬁxed to the support at C and subjected to
the torsional loadings shown. Determine the shear stress at points A and B and sketch the shear stress On volume elements located at these points. Solution 512 ___________,.__.___
TB : gig: 800(0.02) __ 6'79M
J ———————§(O.0354) — . Pa Ans‘ .
3m.» 7;=‘°””“ 73:67pm
2? .+
$41!":
{A = E: 500(0.035)_ 7
J mac0354)  42 MP3 Ans
ﬁ=$oa~m Problem 5—19 The steel shaft is subjected to the torsional loading shown.
Determine the absolute maximum shear stress in the shaft and sketch the shear—stress distribution along a radial line where it is maximum. “xvi Solution 519 __,,,___.....——~—— quus is 3.5 W . m ;, imam, two mm
of the shaft shoukﬁ be; mnsidamd sins: J is diffan
_ T6 = 5(103 new} — tam:
an!!! 7 gmmr ‘22: 8.5(i0’)(0.36} nun
law 7 £40.06)“ = 49.? MP3 = 749.? MPa = 25.1 MP; Ans 4693 48331Mechanics of Solid Student Guide, ‘I'uteria! and AssignmeuterbleIgs PROBLEMS ON SMLE TORSION
141 (a ) For the hollowalminium shaft (G = 27 GPa) shown, if the applied torque
To is 3 kN—m, determine  (i) The shear stress at the inner edge (inner circle ) of the shaft
(ii) The maximum shear stress in the shaft
(iii) The angle of twist (b ) (1) Determine the torque To causing an angle of twist of 2°.
(ii) Determine the angle of twist if the same torque is applied to a solid shaft of the same length and crosssectional area.
40 mm \w . .3 e ‘Tovslm Thao‘ré.‘ _..___.____
§__'___’_T__.£§__= '5
a "d"— "' ,7 "H K 3 _.' o‘.oL\+%q read.  Vii thxxowés’szwgbh _ rmiw"
3 S.%_~A\D“‘ : 9007‘? 'W‘ ‘ ' R
3; PM Ok SDUA ska 4:, " I
‘ 4 “1..— _— :1.—L'..'_':_ _  s R, ..—. Born—mm QS= ——— = \‘1'SQ'ZMDT'TE‘ a _ TL ><\o Kzusmo .
i; Thus) ><\'l lama 7 ‘35:“— :thnu ‘ L 48331Mechanics of Solid Student Guide, Tutorial and Assignmt Problem 143 The solid spindle AB of diameter d3 = 66 mm passes through the sleeve and is
welded to the sleeve at C. The sleeve has an Outer diameter of 80 mm and a Solid Spindle
Hollow Sleeve
Weld
Fanam
I
30 ‘J
Section 321 69 Th: 'A36 swel pests an: "drilled" at census! angu—
f 3 in speed ink) the soil using the rotary ha an inn=r diamem 225 mm. delermine: Eh:
the past with respect to end B whnn the post reaches the depth indicated. Due to soil hicﬁou,assum= 1h: torque along
thc past Van's: Encarly as shown. and a communist] ionqua orEGkNmamatthcbit. I};  30—%(15)(3) ~— 0 2M =‘o;
13 = 102.5 m m
‘2: 1' Mum
1 '1 j
2Mz =0. 102.5~E(Sz)(z)—T=0
T: (102.5 4.53) kN  m I?
3242 UT
‘4; I335 MW“.
“3 JG JG
= '10:.5(103)(4) + [a (102.5—2.522)(103}dz
gaunzs)‘»(0.1)4)(75)(109) a §{(0.1125)4 (0.1)4}(75)(109) ,. .k a
= 0.0980 rad Ans 235 ...
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This note was uploaded on 08/22/2011 for the course ENG 48331 taught by Professor Brown during the Three '11 term at University of Technology, Sydney.
 Three '11
 BROWN

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