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5-13 】解： n n n x 1 sin ] [ 的频谱为： 1 1 0 1 ) ( j e X 设零值插入后的信号为 ] [ 1 n x ，则 3 0 3 ] 3 [ ] [ ] [ ) 3 ( 1 k n k n n x n x n x 应有， ) ( ) ( 3 1 j j e X e X 1 5 3 1 时， ) ( 1 j e X 的结果如题 5.13 图（ a ）所示， 频谱在 3 2 k 处，有宽度为 3 2 1 ，幅度为 1 的矩形脉冲。 ] [ 1 n x 经低通滤波后，将保留 ) ( 1 j e X k 2 处的矩形脉冲，滤除其它地方的脉冲， ) ( ) ( ) ( 1 j j j e H e X e W 最后对 ] [ n w 进行抽取， ] 5 [ ] [ n w n y ] [ n y 的频谱如题 5.12 图（ b ）所示， 可得 , n n n y 5 3 5 sin ] [ 1 2 5 3 1 时，与（ 1 ）的情况类似， ) ( 1 j e X 的频谱在位于 3 2 k ，处有宽度为 3 2 1 ，幅度为 1 的矩形脉冲，

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